ok so i start of with this

$\displaystyle 50 = \frac{2p^2}{(0.4-p)(0.1-p)}$

so rearranging a bit

$\displaystyle 50= \frac{2p^2}{p^2-0.5p+0.04}$

$\displaystyle 2p^2 = 50(p^2-0.5p+0.04)$

$\displaystyle 2p^2= 50p^2-25p+2$

$\displaystyle 48p^2-25p+2=0$

ok so i put in the qudratic forumula and i come out with

x= 0.42212

x=0.09871

my problem is that when i put this value into the original equation i get 100 not 50. What am i doing wrong?