Hey guys can anyone explain to me how to do this problem

Logx243=5/3

base is x

Thanks for the help guys

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- Apr 11th 2010, 04:28 PM #1

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- Apr 11th 2010, 04:34 PM #2

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Use

**the relationship**between logs and exponentials:

. . . . .$\displaystyle y\, =\, x^b$

. . . . .means the same thing as

. . . . .$\displaystyle \log_b(y)\, =\, x$

...to convert the log equation into the corresponding exponential equation. Then convert "243" to a power of three.

- Apr 11th 2010, 04:35 PM #3

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- Apr 11th 2010, 04:43 PM #4

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- Apr 11th 2010, 04:45 PM #5

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- Apr 11th 2010, 04:48 PM #6

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- Apr 11th 2010, 04:52 PM #7

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- Apr 11th 2010, 05:58 PM #8

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- Apr 12th 2010, 03:19 AM #9

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