I have a rational equation 2x/(x-1)-2/(x)=7/(3x-3)
I figured out that x(3x-3) is the LCD, but I have no clue how to cancel it from the first term 2x/(x-1). As always, any help is appreciated!!!
Hello, Mathfailure!
I have a rational equation: .2x/(x-1) - 2/(x) .= .7/(3x-3)
I figured out that x(3x-3) is the LCD . . .
Why didn't you leave the LCD in factored form? . . . 3x(x - 1)
When we multiply through by the LCD, we get:
. . . . . . . . . .2x . . . . . . . . . .2 . . . . . . . . . . . . 7
. . 3x(x - 1)·------ .- .3x(x - 1)·-- . = . 3x(x - 1)·---------
. . . . . . . . .x - 1 . . . . . . . . . x . . . . . . . . . . 3(x - 1)
Now you can cancel, right?