# Thread: need help verifying answer ...

1. ## need help verifying answer ...

so constant = h/w = 25/10

constant = 2.5 , w = 10

2.5 x 10 = 25

would that be the answer ? or just 2.5?

2. Originally Posted by bringash

so constant = h/w = 25/10

constant = 2.5 , w = 10

2.5 x 10 = 25

would that be the answer ? or just 2.5?
Dear bringash,

I think this is one of your online exam questions. Therefore you are to do this yourself and I hope that the moderators of this forum will look into this matter.

3. Originally Posted by Sudharaka
Dear bringash,

I think this is one of your online exam questions. Therefore you are to do this yourself and I hope that the moderators of this forum will look into this matter.
Will if you would really like to know ... my nephew who is in 9th grade asked me to help him with his algebra 2 homework that the teacher gives him online ... there are some that I am not sure about; thus, wanting to help my nephew understand this material to the fullest of his abilities i asked for some help ... you know what happens when you assume right sudharaka?

4. Dear bringash,

In that case (thinking my assumption is incorrect!!) I shall give you my ideas about the question. The answer 2.5 is correct.

$Constant=\frac{H(w)}{w}=\frac{25.00}{10.0}=2.50$ ; (using the rules of significant figures.)

Since it is given that the answer could be rounded to first decimal place 2.5 is also correct.

Hope this will help you.

P.S: If you felt angry about my previous post I am really sorry about it. But MHF does not encourage any of it's members to give exam help.

5. Originally Posted by Sudharaka
Dear bringash,

In that case (thinking my assumption is incorrect!!) I shall give you my ideas about the question. The answer 2.5 is correct.

$Constant=\frac{H(w)}{w}=\frac{25.00}{10.0}=2.50$ ; (using the rules of significant figures.)

Since it is given that the answer could be rounded to first decimal place 2.5 is also correct.

Hope this will help you.

P.S: If you felt angry about my previous post I am really sorry about it. But MHF does not encourage any of it's members to give exam help.
haha no i wasn't angry bro don't worry about it, it was me being a di*k not you ... thanks alot bro

6. hey would the answer to this be x/2 (d) or (c) ? I am not completely sure although i think its d

7. It can't be (d), try it with x = 2.

Generally $\sqrt{a}\sqrt{b} = \sqrt{ab}$...

8. Originally Posted by maddas
It can't be (d), try it with x = 2.

Generally $\sqrt{a}\sqrt{b} = \sqrt{ab}$...

i know it can either be (b) or (d), but im pretty sure it is B, am i wrong? if so how come ?

9. You are correct. (I loled at "acceptable values of x".)

10. Originally Posted by maddas
You are correct. (I loled at "acceptable values of x".)
yeah bro the wording for some of these problems kills me haha

11. so if what i did for the other problem was correct ... the answer to this problem

would be (b) ?

12. Ja.

13. Originally Posted by maddas
Ja.

How would I solve this problem?

14. Use $\sqrt{a}\sqrt{b} = \sqrt{ab}$ to slit it up into $\sqrt{2}\sqrt{x^2}\sqrt{4}\sqrt{x}$, simplify, and then put the remaining radicals back together.

15. Originally Posted by maddas
Use $\sqrt{a}\sqrt{b} = \sqrt{ab}$ to slit it up into $\sqrt{2}\sqrt{x^2}\sqrt{4}\sqrt{x}$, simplify, and then put the remaining radicals back together.

according to that the answer would be (d) ?

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