http://i43.tinypic.com/25auvfd.jpg

so constant = h/w = 25/10

constant = 2.5 , w = 10

2.5 x 10 = 25

would that be the answer ? or just 2.5?

Printable View

- Apr 10th 2010, 06:42 AMbringashneed help verifying answer ...
http://i43.tinypic.com/25auvfd.jpg

so constant = h/w = 25/10

constant = 2.5 , w = 10

2.5 x 10 = 25

would that be the answer ? or just 2.5? - Apr 10th 2010, 06:57 AMSudharaka
- Apr 10th 2010, 07:12 AMbringash
Will if you would really like to know ... my nephew who is in 9th grade asked me to help him with his algebra 2 homework that the teacher gives him online ... there are some that I am not sure about; thus, wanting to help my nephew understand this material to the fullest of his abilities i asked for some help ... you know what happens when you assume right sudharaka?

- Apr 10th 2010, 07:30 AMSudharaka
Dear bringash,

In that case (thinking my assumption is incorrect!!) I shall give you my ideas about the question. The answer 2.5 is correct.

$\displaystyle Constant=\frac{H(w)}{w}=\frac{25.00}{10.0}=2.50$ ; (using the rules of significant figures.)

Since it is given that the answer could be rounded to first decimal place 2.5 is also correct.

Hope this will help you.

P.S: If you felt angry about my previous post I am really sorry about it. But MHF does not encourage any of it's members to give exam help. - Apr 10th 2010, 07:42 AMbringash
- Apr 10th 2010, 08:38 AMbringash
http://i42.tinypic.com/29qgydx.jpg

hey would the answer to this be x/2 (d) or (c) ? I am not completely sure although i think its d - Apr 10th 2010, 08:44 AMmaddas
It can't be (d), try it with x = 2.

Generally $\displaystyle \sqrt{a}\sqrt{b} = \sqrt{ab}$... - Apr 10th 2010, 09:26 AMbringash
http://i41.tinypic.com/29woisp.jpg

i know it can either be (b) or (d), but im pretty sure it is B, am i wrong? if so how come ? - Apr 10th 2010, 09:28 AMmaddas
You are correct. (I loled at "acceptable values of x".)

- Apr 10th 2010, 09:37 AMbringash
- Apr 10th 2010, 09:40 AMbringash
so if what i did for the other problem was correct ... the answer to this problem

http://i44.tinypic.com/2444ha9.jpg

would be (b) ? - Apr 10th 2010, 09:51 AMmaddas
Ja.

- Apr 10th 2010, 09:59 AMbringash
http://i44.tinypic.com/2zoad6f.jpg

How would I solve this problem? - Apr 10th 2010, 10:11 AMmaddas
Use $\displaystyle \sqrt{a}\sqrt{b} = \sqrt{ab}$ to slit it up into $\displaystyle \sqrt{2}\sqrt{x^2}\sqrt{4}\sqrt{x}$, simplify, and then put the remaining radicals back together.

- Apr 10th 2010, 10:16 AMbringash