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Math Help - binomial expansion

  1. #1
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    binomial expansion

    Find the coefficient of \frac{1}{x^3} in the expansion of (x-1)^3 (\frac{1}{x}+x)^6.
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  2. #2
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    Quote Originally Posted by shawli View Post
    Find the coefficient of \frac{1}{x^3} in the expansion of (x-1)^3 (\frac{1}{x}+x)^6.
    Expansion of (x - 1)^3 = x^3 - 3x^2 + 3x - 1
    First two terms of (1/x + x )^6 = 1/x^6 + 6/x^4 + ...........
    So 1/x^3 term will be available by the product of x^3*1/x^6 and 3x*6/x^4
    So the coefficient of 1/x^3 = ........?
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