Hello BadMonkey Originally Posted by
BadMonkey Thanks
I got that but I was no sure if it was correct
but I done it this way y-y1=m(x-x1)
You can certainly use
$\displaystyle y-y_1=m(x-x_1)$
to get the equation of the line. Using
$\displaystyle x_1=1,\;y_1=0$ and $\displaystyle m = -1$
gives
$\displaystyle y-0=-1(x-1)$
$\displaystyle \Rightarrow y = 1-x$
But this line doesn't make sense, and is not correct: Originally Posted by
BadMonkey 1-x=0(1-x)
would it be correct to write it like this also?
Grandad