How do I answer this log equation?

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- Apr 9th 2010, 02:30 PM #1

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- Oct 2009
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- Apr 9th 2010, 02:39 PM #2

- Apr 9th 2010, 04:58 PM #3

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- Lexington, MA (USA)
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- Apr 10th 2010, 09:34 AM #4