Am stuck again. Anyone have any ideas?
In a stream whose current flows at the speed of 3 miles/hr, a man rowed upstream and returned to his starting point in 6.25 hr. If the man rows at a speed of 5 mi/hr, in still water, how long did he row upstream.
Tup + Tdown = 6.25 Hrs.
Vup = (Vman - 3)
Vdown = (Vman + 3)
Dup = Ddown = D , Tup (Vb-3) = Tdown (Vb+3)
D / (Vman - 3) + D / (Vman + 3) = 6.25 Hrs