1. ## Simplifying exponents

however i get a different calculation
(27)^-1/3 = 9

(27)^-1/3 = 9 * 2/9 = -2/3 then -2/3 * -27 = 54/3Q = 18/Q

2. Hello,

$27^{\frac{-1}{3}} = \frac{1}{3} \neq 9$

It should work out fine now.

3. Originally Posted by Bacterius
Hello,

$27^{\frac{-1}{3}} = \frac{1}{3} \neq 9$

It should work out fine now.
27^-1/3 is -1/3 then?

2/9*-(1/3) = 2/27

then -2/27 * 27/q = 54/27Q = 2/1q =2/q
is that correct

4. Originally Posted by matlondon
27^-1/3 is -1/3 then?

2/9*-(1/3) = 2/27

then -2/27 * 27/q = 54/27Q = 2/1q =2/q
is that correct
No. 27^(-1/3) = 1/3. Try without the minus sign.

5. Originally Posted by matlondon
27^-1/3 is -1/3 then?

2/9*-(1/3) = 2/27

then -2/27 * 27/q = 54/27Q = 2/1q =2/q
is that correct
Note that
$27=3^3$
so $
27^-1/3 = (3^3)^-1/3$

where the exponents cancel and we are left with 1/3. There is no negative, the negative exponent simply indicates that we have 1 over the value.