I can't seem to figure these two questions out. A little assistance please?
x^2/3 + 2x^1/3 - 63 = 0
The solution set is ( , )
For each given pair of numbers find a quadratic equation with integral coefficients that has the numbers as its solutions.
I got x^2 + 16 for that. I think it's right. Thanks a lot!
I have a couple more that are bothering me now. If you could help that would be great. If not, I understand...
x^2/3 + 3x^1/3 - 28 = 0
Solution set is ( , )
I tried doing this the same way you did the first one but I'm not getting it!
Find the vertex
a= x^2 + 18x - 8