1. ## Find f(g(-3))

When f(x)=x^2-1 and g(x)=x+2

If someone could help me with first step I could probably do the rest.

Thanks,

2. Hi!

Try sticking the expressions for $g(x)$into the place of the x in the expression of $f(x)$.
$
f(g(x))=(x+2)^2-1
$
.

Hope this helps... I'm not mathematician.

3. Originally Posted by Tally
When f(x)=x^2-1 and g(x)=x+2

If someone could help me with first step I could probably do the rest.

Thanks,
$g(-3) = -3+2 = -1$

$f(g(-3))= (-1)^{2} -1 = 1-1 = 0$

4. Originally Posted by harish21
$g(-3) = -3+2 = -1$

$f(g(-3))= (-1)^{2} -1 = 1-1 = 0$
Awesome Thank you. I understand it much clearer now.