p(t) = 100*(2^2t)
would i have to multiply the 100 and the 2 or just leave it like that? i'm confusing myself with the logarithmic law..
edit: thank you integral!
p(t) = 100*(2^2t)
would i have to multiply the 100 and the 2 or just leave it like that? i'm confusing myself with the logarithmic law..
edit: thank you integral!
$\displaystyle P(t)=100(2^{2t}) \Rightarrow \frac{P(t)}{100}=2^{2t}$
thus:
$\displaystyle log_2\frac{P(t)}{100}=2t \,\,\,\because \,\,\,a^x=b\Rightarrow log_ab=x$
then:
$\displaystyle \frac{1}{2}log_2\frac{P(t)}{100}=t$
$\displaystyle log_2\sqrt{\frac{P(t)}{100}}=t$
$\displaystyle
log_2\frac{\sqrt{P(t)}}{10}=t$