p(t) = 100*(2^2t)

would i have to multiply the 100 and the 2 or just leave it like that? i'm confusing myself with the logarithmic law..

edit: thank you integral!

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- Apr 7th 2010, 06:33 PMkelvinly[SOLVED] putting a exponential growth function to log form
p(t) = 100*(2^2t)

would i have to multiply the 100 and the 2 or just leave it like that? i'm confusing myself with the logarithmic law..

edit: thank you integral! - Apr 7th 2010, 07:16 PMintegral
$\displaystyle P(t)=100(2^{2t}) \Rightarrow \frac{P(t)}{100}=2^{2t}$

thus:

$\displaystyle log_2\frac{P(t)}{100}=2t \,\,\,\because \,\,\,a^x=b\Rightarrow log_ab=x$

then:

$\displaystyle \frac{1}{2}log_2\frac{P(t)}{100}=t$

$\displaystyle log_2\sqrt{\frac{P(t)}{100}}=t$

$\displaystyle

log_2\frac{\sqrt{P(t)}}{10}=t$ - Apr 7th 2010, 07:17 PMSudharaka
Dear integral,

There is a little typo in the first line. It should be, $\displaystyle P(t)=100(2^{2t}) \Rightarrow \frac{P(t)}{100}=2^{2t}$ - Apr 7th 2010, 07:23 PMintegral
I really meant$\displaystyle 2^{2t}$, but thank you (Wink)

- Apr 7th 2010, 07:24 PMkelvinly
- Apr 8th 2010, 03:23 AMHallsofIvy