
Basic rearranging
I am currently solving questions preparing for my mechanics exam and I am struggling with the final part of the question I have the following equation
yyo=Vo*sin(beta)*x^2/Vo*cos(beta)1/2*g*x^2/Vo^2cos^2(beta)
I need to solve this for Vo any help would be much appreciated

I'm sorry but this is ambigious. I'll just put what I think the equation is into proper LaTeX form, and please tell us if this is the right one.
$\displaystyle y  y_0=V_0 \times \sin{(\beta)} \times \frac{x^2}{V_0} \times \cos{(\beta)}  \frac{1}{2} \times g \times \frac{x^2}{V_0^2} \times \cos^2{(\beta)}$
Is this the one ? (Whew)

Sorry your right that is the correct equation could you please point me in the right direction on how to solve for Vo

Assuming that is correct the $\displaystyle V_0$ and $\displaystyle \frac{1}{V_0}$ in the first term will cancel leaving
$\displaystyle y y_0= sin(\beta)cos(\beta)\frac{1}{2}g\frac{x^2}{V_0^2}cos^2(\beta)$
Subtract $\displaystyle sin(\beta)cos(\beta)$ from both sides:
$\displaystyle y y_0 sin(\beta)cos(\beta)= \frac{1}{2}g\frac{x^2}{V_0^2}cos^2(\beta)$
Multiply both sides by $\displaystyle V_0^2$:
$\displaystyle V_0^2(y y_0 sin(\beta)cos(/beta))= \frac{1}{2}gx^2cos^2(\beta)$
Divide both sides by $\displaystyle y y_0 sin(\beta)cos(/beta)$:
$\displaystyle V_0^2= \frac{gx^2cos^2(\beta)}{2(y y_0 sin(\beta)cos(\beta)}$
And, finally, take the square root of both sides:
$\displaystyle V_0= \sqrt{\frac{gx^2cos^2(\beta)}{2(y y_0 sin(\beta)cos(\beta))}}$
$\displaystyle V_0= \sqrt{\frac{gx^2 cos^2(\beta)}{2(sin(\beta)cos(\beta) y+ y_0)}}$

thankyou this has been very helpful