3(g-3)=6 How do I do these problems? (BTW: I understood the things of the 4 variable things).
Last edited by mr fantastic; April 9th 2010 at 02:47 AM. Reason: Changed post title
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To solve for You can first divide both sides of the equation by 3, giving: then add 3 to both sides:
3(x+1)=21 -3 -3 x+1=18 -1 -1 x=17? The numbers are aligned kind of wrong, but you get the idea. Is the answer right?
Originally Posted by hoiguy1208 3(x+1)=21 -3 -3 x+1=18 -1 -1 x=17? The numbers are aligned kind of wrong, but you get the idea. Is the answer right? Step 1 3(x+1)=3x+3 (multiply out the bracket) Step 2 3x+3=21 (-3 from both side) 3x=18 Step 3 3x=18 (divide both side by 3) x=6. does this help?
Thank you. On problems like: 6(3d+5) =75, do I take a similar approach?
Originally Posted by hoiguy1208 Thank you. On problems like: 6(3d+5) =75, do I take a similar approach? yes
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