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Math Help - Solving linear equation.

  1. #1
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    Solving linear equation.

    3(g-3)=6

    How do I do these problems?

    (BTW: I understood the things of the 4 variable things).
    Last edited by mr fantastic; April 9th 2010 at 03:47 AM. Reason: Changed post title
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  2. #2
    Senior Member Stroodle's Avatar
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    To solve for g

    You can first divide both sides of the equation by 3, giving:

    g-3=2

    then add 3 to both sides:

    g=5
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  3. #3
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    Attempt at another problem

    3(x+1)=21
    -3 -3

    x+1=18
    -1 -1

    x=17?


    The numbers are aligned kind of wrong, but you get the idea.
    Is the answer right?
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  4. #4
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    3(g-3)=6  \mbox{   / in both sides } \frac{1}{3}
    \Leftrightarrow{\frac{3(g-3)}{3}=\frac{6}{3}}
    \Leftrightarrow{(g-3)=2}\mbox{   / in both sides plus +3}
    \Leftrightarrow{g-3+3=2+3}
    \Leftrightarrow{g=5} \mbox{ end}
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  5. #5
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    Quote Originally Posted by hoiguy1208 View Post
    3(x+1)=21
    -3 -3

    x+1=18
    -1 -1

    x=17?


    The numbers are aligned kind of wrong, but you get the idea.
    Is the answer right?
    Step 1
    3(x+1)=3x+3 (multiply out the bracket)

    Step 2
    3x+3=21 (-3 from both side)
    3x=18

    Step 3
    3x=18 (divide both side by 3)
    x=6.

    does this help?
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  6. #6
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    Thank you. On problems like:

    6(3d+5) =75, do I take a similar approach?
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  7. #7
    MHF Contributor
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    Quote Originally Posted by hoiguy1208 View Post
    Thank you. On problems like:

    6(3d+5) =75, do I take a similar approach?
    yes
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