Solving linear equation.

3(g-3)=6

How do I do these problems?

(BTW: I understood the things of the 4 variable things).

To solve for

You can first divide both sides of the equation by 3, giving:



then add 3 to both sides:

3(x+1)=21
-3 -3

x+1=18
-1 -1

x=17?


The numbers are aligned kind of wrong, but you get the idea.
Is the answer right?

Quote:

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Originally Posted by hoiguy1208

3(x+1)=21
-3 -3

x+1=18
-1 -1

x=17?


The numbers are aligned kind of wrong, but you get the idea.
Is the answer right?

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Step 1
3(x+1)=3x+3 (multiply out the bracket)

Step 2
3x+3=21 (-3 from both side)
3x=18

Step 3
3x=18 (divide both side by 3)
x=6.

does this help?

Thank you. On problems like:

6(3d+5) =75, do I take a similar approach?

Quote:

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Originally Posted by hoiguy1208

Thank you. On problems like:

6(3d+5) =75, do I take a similar approach?

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yes