3(g-3)=6

How do I do these problems?

(BTW: I understood the things of the 4 variable things).

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- Apr 6th 2010, 06:30 PMhoiguy1208Solving linear equation.
3(g-3)=6

How do I do these problems?

(BTW: I understood the things of the 4 variable things). - Apr 6th 2010, 06:34 PMStroodle
To solve for $\displaystyle g$

You can first divide both sides of the equation by 3, giving:

$\displaystyle g-3=2$

then add 3 to both sides:

$\displaystyle g=5$ - Apr 6th 2010, 06:53 PMhoiguy1208Attempt at another problem
3(x+1)=21

-3 -3

x+1=18

-1 -1

x=17?

The numbers are aligned kind of wrong, but you get the idea.

Is the answer right? - Apr 6th 2010, 07:47 PMxSquall
$\displaystyle 3(g-3)=6 \mbox{ / in both sides } \frac{1}{3} $

$\displaystyle \Leftrightarrow{\frac{3(g-3)}{3}=\frac{6}{3}}$

$\displaystyle \Leftrightarrow{(g-3)=2}\mbox{ / in both sides plus +3}$

$\displaystyle \Leftrightarrow{g-3+3=2+3}$

$\displaystyle \Leftrightarrow{g=5} \mbox{ end}$ - Apr 6th 2010, 10:17 PMBabyMilo
- Apr 7th 2010, 12:32 AMhoiguy1208
Thank you. On problems like:

6(3d+5) =75, do I take a similar approach? - Apr 7th 2010, 12:39 AMmathaddict