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hi, im powering through an advanced functions course right now by myself at home and could use some help.
1. Given that log 2 5 aproximately equals 2.3219
find an aproximation for log 2 20
2. 2log m + 3log m = 10 where there is no base on the logarithm.
thanks in advanced(crappy pun intended)
1. $\displaystyle \log_2(20) = \log_2(4 \cdot 5) = \log_2(4) + \log_2(5)$Quote:
Originally Posted by way123
2. no base is usually base 10 for beginners ...
$\displaystyle 2\log{m} + 3\log{m} = 5\log{m} = 10$
$\displaystyle \log{m} = 2$
change to an exponential equation to find $\displaystyle m$
wouldnt 5logm=10 be equivalent to log m^5=10
and in that case m is not equal to 2.
where am i going wrong?
$\displaystyle log(x)$ usually means $\displaystyle log_{10}(x)$
and
$\displaystyle log_a(b)=c\Rightarrow a^c=b$
m does not equal 2 ... $\displaystyle \log(m) = 2$Quote:
Originally Posted by way123
$\displaystyle m = 10^2$
