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Math Help - Stuff i should know.

  1. #1
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    Stuff i should know.

    Even though i am a complete math junkie, and am in the last term of first year calculus--which i understand pretty well, i am often vexed by algebra. Seems ridiculous, don't it?

    Anyway, along the way of solving the derivative of a parametric, to find the equations of tangent lines at a point, I've run into the road block that i show in the attachment.

    Sorry that it's an attachment. Not so sue about latex yet (just joined up today) and i detest the thought of keyboard entered math stuff.


    Thanks!
    Attached Thumbnails Attached Thumbnails Stuff i should know.-capture.jpg  
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  2. #2
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    You are correct! sqrt(3)=3/sqrt(3)
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  3. #3
    MHF Contributor harish21's Avatar
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    Quote Originally Posted by boardguy67 View Post
    Even though i am a complete math junkie, and am in the last term of first year calculus--which i understand pretty well, i am often vexed by algebra. Seems ridiculous, don't it?

    Anyway, along the way of solving the derivative of a parametric, to find the equations of tangent lines at a point, I've run into the road block that i show in the attachment.

    Sorry that it's an attachment. Not so sue about latex yet (just joined up today) and i detest the thought of keyboard entered math stuff.


    Thanks!
    You should know that:

    3 = \sqrt{3} \times \sqrt{3}

    So,


     \pm \frac{3}{\sqrt{3}} = \pm \frac{\sqrt{3} \times \sqrt{3}}{\sqrt{3}} = \pm \sqrt{3}

    Done!
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  4. #4
    Senior Member Stroodle's Avatar
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    They've rationalised the denominator:

    \frac{3}{\sqrt{3}}\times\frac{\sqrt{3}}{\sqrt{3}}=  \frac{3\sqrt{3}}{3}=\sqrt{3}
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