Given that log a 16= x and log a 12 = y, express loga3 in terms of x and y.
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Originally Posted by Sxtxs Given that log a 16= x and log a 12 = y, express loga3 in terms of x and y. . Therefore . . Therefore . So .
Suppose: Express in terms of x&y. We can know that: or We can also infer, if that: So we have: and Therefore: Like wise: Test: If then so & x=12log_32 So The test values where derived from:
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