Given that log a 16= x and log a 12 = y, express loga3 in terms of x and y.

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- April 6th 2010, 07:22 AMSxtxsLogarithms
Given that log a 16= x and log a 12 = y, express loga3 in terms of x and y.

- April 6th 2010, 07:28 AMProve It
- April 6th 2010, 04:46 PMintegral
Suppose:

Express in terms of x&y.

We can know that:

or

We can also infer, if that:

So we have:

and

Therefore:

Like wise:

Test:

If

then

so

&

x=12log_32

So

The test values where derived from: