Hi,

If you were given, say: x-intercept of -4, y-intercept of -2, vertical asymptote x=2, and horizontal asymptote y=1. How do you find the equation for a rational function with these features?

Thanks in advance.

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- Apr 5th 2010, 01:01 PMHelloooRational Functions
Hi,

If you were given, say: x-intercept of -4, y-intercept of -2, vertical asymptote x=2, and horizontal asymptote y=1. How do you find the equation for a rational function with these features?

Thanks in advance. - Apr 5th 2010, 02:55 PMskeeter
- Apr 6th 2010, 03:25 PMHellooo
Thanks, but can you show the steps in how you reached the answer?

- Apr 9th 2010, 05:36 PMmr fantastic
The simplest model to use is . Your job is to find the values of a, b and c using the given information. You will get an answer equivalent to

**skeeter**'s.

In fact, the only information required is vertical asymptote x=2, horizontal asymptote y=1 and y-intercept of -2. The information x-intercept of -4 can be used to check your answer. - Apr 9th 2010, 07:33 PMAllanCuz
To supplement to Mr. Fantastic's information: horizontal asymptotes occur in the numerator and vertical asymptotes occur in denominator. If you recall a function cannot cross an asymptote (always in the case of vertical, most times true in the case of horizontal). Which means that the function cannot be a certain value there.

Thus, if a vertical asymptote of 2 exists we must have (x - 2) in the denominator.

Also recall that at the x-intercept y = 0, thus we must have (x+4) in the numerator because our x-intercept of -4 makes this equation 0.