Since you are dividing the two's both in the numerator and the denominator each of them cancel out and you are left with:
Hi, I'm having a slight bit of trouble grasping the concept of the general quadratic formula, the part that involves surds.
I have the question: Simplify 2+2 to the square root of 5 divided by 2.
I also have a few other things i may need assistance on, but i'll start here.
The quadratic formula is not a concept, it's just a formula. you just plug stuff into it to find the answer. the concept behind the quadratic formula is called completing the square, you will have to learn that method of solving quadratics as well.
The quadratic formula says:
Given a quadratic of the form
ax^2 + bx + c = 0
then the roots are given by the formula
x = [-b +/- sqrt(b^2 - 4ac)]/2a
so you just plug in the numbers in their respective positions.
e.g. Solve 2x^2 + 5x + 1 = 0
=> x = [-5 +/- sqrt(25 - 4(2)(1)]/2*2 = [-5 +/- sqrt(17)]/4
so x = [-5 + sqrt(17)]/4 or x = [-5 - sqrt(17)]/4
Note: the roots of a function of x are the x values that cause the function to be zero. so once we have a quadratic = 0, solving for x gives the roots
Ahh, i think my meaning was misinterpreted.
I mean by 2+2 to the square root of 5 divided by 2 as everything past the divide is the numerator, and the 2 is the dinominator
qbkr21, how did you make that picture, i would be able to show you if i had that program
I use LaTeX.
You can use the one they have on Wikipedia.
Use <math></math> to type code.
You can also use one they have on PlanetMath