I'm stuck on this problem, can someone explain how to do this for me?
x+3/x+5 + 6/x^2 + 3x - 10
factor the denominator of the second term ...
$\displaystyle \frac{x+3}{x+5} + \frac{6}{(x+5)(x-2)}
$
common denominator is $\displaystyle (x+5)(x-2)$ ...
$\displaystyle \frac{(x+3)(x-2)}{(x+5)(x-2)} + \frac{6}{(x+5)(x-2)}
$
add the fractions ...
$\displaystyle \frac{(x+3)(x-2)+6}{(x+5)(x-2)}$
finish by multiplying the two binomials in the numerator and combining like terms.
fyi ... one simplifies an expression or solves an equation. there is a difference.