# Thread: solve for x: log(base e)((x+4)/2)=2e^(x)-4

1. ## solve for x: log(base e)((x+4)/2)=2e^(x)-4

log(base e)((x+4)/2)=2e^(x)-4

can you please explain how to solve this for x,
thanks

2. Originally Posted by emma
log(base e)((x+4)/2)=2e^(x)-4

can you please explain how to solve this for x,
thanks
I don't see an analytic solution for this being possible so I'd suggest an iterative method.

$\displaystyle \ln (x+4) - \ln 2 = 2e^x - 4$

$\displaystyle 4 - \ln 2 = 2e^x - \ln(x+4)$

Wolfram gives approximations of $\displaystyle x \approx -3.96$ and $\displaystyle x \approx 0.895$

3. oh, maybe im supposed to do it on a calculator then..i don't know what an iterative method is, or what the 'In' means... but thanks anyway

4. Originally Posted by emma
oh, maybe im supposed to do it on a calculator then..i don't know what an iterative method is, or what the 'In' means... but thanks anyway
A graphics calculator would work but a standard one wouldn't. Iterative methods are largely finding a rough solution by trial and error, to converge on the answer.

Also $\displaystyle \ln (x) = \log_e(x)$