Thread: simplification of exponential expression

[(x^2 y^-2)^-1]^-1=
(1/x^2 y^-2)^-1=
(y^2/x^2)-1=
x^2/y^2
this solution is right according to the back of the book, are the steps also correct?

Originally Posted by dymand68

[(x^2y^-2)^-1]^-1=
(1/x^2y^-2)^-1=
(y^2/x^2)-1=
x^2/y^2
this solution is right according to the back of the book, are the steps also correct?

.

ty.........so the correct order of operations starts with the negative exponent OUTSIDE the brackets?