[(x^2 y^-2)^-1]^-1= (1/x^2 y^-2)^-1= (y^2/x^2)-1= x^2/y^2 this solution is right according to the back of the book, are the steps also correct?
Last edited by dymand68; Apr 1st 2010 at 06:05 PM.
Follow Math Help Forum on Facebook and Google+
Originally Posted by dymand68 [(x^2y^-2)^-1]^-1= (1/x^2y^-2)^-1= (y^2/x^2)-1= x^2/y^2 this solution is right according to the back of the book, are the steps also correct? .
ty.........so the correct order of operations starts with the negative exponent OUTSIDE the brackets?
View Tag Cloud