[(x^2 y^-2)^-1]^-1= (1/x^2 y^-2)^-1= (y^2/x^2)-1= x^2/y^2 this solution is right according to the back of the book, are the steps also correct?
Last edited by dymand68; April 1st 2010 at 07:05 PM.
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Originally Posted by dymand68 [(x^2y^-2)^-1]^-1= (1/x^2y^-2)^-1= (y^2/x^2)-1= x^2/y^2 this solution is right according to the back of the book, are the steps also correct? .
ty.........so the correct order of operations starts with the negative exponent OUTSIDE the brackets?
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