Math Help - fractional exponent simplification

1. fractional exponent simplification

7x^2 / x^3=
7x^2-3=
7x^-1=
1/7x
this is wrong, please point out how-so

2. Originally Posted by dymand68
7x^2 / x^3=
7x^2-3=
7x^-1=
1/7x
this is wrong, please point out how-so

$
7x^{-1}= \frac{7}{x}
$

3. this makes sense to me
7x^2 / x^3=
7x^2-3=
7x^-1=
(7/1)(1/x)=
7/x

4. Originally Posted by dymand68
x^-1=
1/x
?
Yep , that is correct.

$x^{-a} = \frac{1}{x^a}, \forall a \in \mathbb{R}$

$\frac{7x^2}{x^3}= \frac{7\times x\times x}{x\times x\times x} = \frac{7}{x}$