7x^2 / x^3= 7x^2-3= 7x^-1= 1/7x this is wrong, please point out how-so
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Originally Posted by dymand68 7x^2 / x^3= 7x^2-3= 7x^-1= 1/7x this is wrong, please point out how-so $\displaystyle 7x^{-1}= \frac{7}{x} $
this makes sense to me 7x^2 / x^3= 7x^2-3= 7x^-1= (7/1)(1/x)= 7/x
Originally Posted by dymand68 x^-1= 1/x ? Yep , that is correct. $\displaystyle x^{-a} = \frac{1}{x^a}, \forall a \in \mathbb{R}$ $\displaystyle \frac{7x^2}{x^3}= \frac{7\times x\times x}{x\times x\times x} = \frac{7}{x} $
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