Could somebody explain how we get the 2nd equation from the 1st? 1) 3 (x − 3)^3 (x + 5)^2 − 3 (x + 5)^3 (x − 3)^2 2) 3 (x − 3)^2 (x + 5)^2 [(x − 3) − (x + 5)]
Follow Math Help Forum on Facebook and Google+
Originally Posted by p75213 1) 3(x − 3)^3 (x + 5)^2 − 3(x + 5)^3 (x − 3)^2 2) 3(x − 3)^2 (x + 5)^2 [(x − 3) − (x + 5)] let a = x-3 and b = x+5 3a^3 b^2 - 3a^2 b^3 3a^2 b^2(a - b) Kapish?
Last edited by Wilmer; Mar 31st 2010 at 07:57 PM. Reason: correct typo
Sorry. Still don't get it. Wouldn't 3a^2b^2(a-b) expand into 3a^3b^2-3a^2b^3. Seems like I am missing something here.
Originally Posted by p75213 Could somebody explain how we get the 2nd equation from the 1st? 1) 3 (x − 3)^3 (x + 5)^2 − 3 (x + 5)^3 (x − 3)^2 2) 3 (x − 3)^2 (x + 5)^2 [(x − 3) − (x + 5)] I think they just factored out a common term: If you were to multiply it out, you should get back to the first expression.
Originally Posted by p75213 Wouldn't 3a^2b^2(a-b) expand into 3a^3b^2-3a^2b^3. Yes. I made typo; now corrected. But still same idea...
Yep - that's it. Many thanks.
View Tag Cloud