Thread: Solve for "X" when added to the Square of Number

The positive integer X is divisible by 25. If [sqrt]X (square root of X) is greater than 25, what integer between 22 and 26, inclusive, could be the value of X/25?


I guessed the answer to be 26. The key I have says the answer = 26. I just can't figure out how really?

Originally Posted by thecapaccino

The positive integer X is divisible by 25. If [sqrt]X (square root of X) is greater than 25, what integer between 22 and 26, inclusive, could be the value of X/25?


I guessed the answer to be 26. The key I have says the answer = 26. I just can't figure out how really?

X=25n for some integer n.

sqrt(X) = 5 sqrt(n)>25, so sqrt(n)>5 and so n>25.

But n=X/25 and we have seen that n>25, and the only option in the given
range is n=26.

RonL