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Math Help - More log questions

  1. #1
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    More log questions

    Hi
    I am having trouble with the following question:
    1)Make the independent varaible the subject of the equation:
    x(t) = \frac{e^t - 1}{e^t + 1}

    P.S
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  2. #2
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    Quote Originally Posted by Paymemoney View Post
    Hi
    I am having trouble with the following question:
    1)Make the independent varaible the subject of the equation:
    x(t) = \frac{e^t - 1}{e^t + 1}

    P.S
    Dear Paymemoney,

    x(t) = \frac{e^t - 1}{e^t + 1}

    x(t)(e^t+1)=e^t-1

    x(t)e^t-e^t+x(t)+1=0

    e^t[x(t)-1]=-[x(t)+1]

    e^t=\frac{-[x(t)+1]}{x(t)-1}

    t=ln\left(\frac{-[x(t)+1]}{x(t)-1}\right)

    Hope this helps you.
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