3x² + 12x -5 / 3x² - 3x
------------ --------
x² + 2x -15 3x - x²
can anyone solve this for me or give some help? im completely stuck.. dotted lines are supposed to be just solid lines, idk how to do it otherwise
3x² + 12x -5 / 3x² - 3x
------------ --------
x² + 2x -15 3x - x²
can anyone solve this for me or give some help? im completely stuck.. dotted lines are supposed to be just solid lines, idk how to do it otherwise
Hello, direction!
I'm guessing that there is a typo in the problem.
Simplify: .$\displaystyle \frac{3x^2 + {\color{red}2}x - 5}{x^2+2x-15} \div \frac{3x^2-3x}{3x-x^2}$
"Invert and multiply": .$\displaystyle \frac{3x^2+2x-5}{x^2+2x-15} \cdot\frac{3x - x^2}{3x^2-3x}$
Factor: .$\displaystyle \frac{(x-1)(3x+5)}{(x-3)(x+5)} \cdot \frac{-x(x-3)}{3x(x-1)} $
Reduce: .$\displaystyle \frac{{\color{green}\rlap{//////}}(x-1)(3x+5)}{{\color{red}\rlap{//////}}(x-3)(x+5)} \cdot \frac{-{\color{blue}\rlap{/}}x{\color{red}\rlap{//////}}(x-3)}{3{\color{blue}\rlap{/}}x{\color{green}\rlap{//////}}(x-1)} $
Answer: .$\displaystyle -\,\frac{3x+5}{3(x+5)} $
Hi direction,
$\displaystyle \frac{3\left(x^2+4x-5\right)}{x^2+2x-15} \cdot \frac{x\left(3-x\right)}{3x\left(x-1\right)}$ = $\displaystyle \frac{{\color{blue}\rlap{/}}3{\color{green}\rlap{///////}}\left(x+5\right){\color{red}\rlap{///////}}\left(x-1\right)}{{\color{green}\rlap{///////}}\left(x+5\right){\color{yellow}\rlap{///////}}\left(x-3\right)}\cdot\frac{{\color{blue}\rlap{/}}x\left({-1}\right){\color{yellow}\rlap{///////}}\left(x-3\right)}{{\color{blue}\rlap{//}}3x{\color{red}\rlap{///////}}\left(x-1\right)}$
Hence, answer is -1