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Math Help - Perform the indicated operations and express in simplest form:

  1. #1
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    Perform the indicated operations and express in simplest form:

    3x + 12x -5 / 3x - 3x
    ------------ --------
    x + 2x -15 3x - x


    can anyone solve this for me or give some help? im completely stuck.. dotted lines are supposed to be just solid lines, idk how to do it otherwise
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  2. #2
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    Hello, direction!

    I'm guessing that there is a typo in the problem.


    Simplify: . \frac{3x^2 + {\color{red}2}x - 5}{x^2+2x-15} \div \frac{3x^2-3x}{3x-x^2}

    "Invert and multiply": . \frac{3x^2+2x-5}{x^2+2x-15} \cdot\frac{3x - x^2}{3x^2-3x}


    Factor: . \frac{(x-1)(3x+5)}{(x-3)(x+5)} \cdot \frac{-x(x-3)}{3x(x-1)}


    Reduce: . \frac{{\color{green}\rlap{//////}}(x-1)(3x+5)}{{\color{red}\rlap{//////}}(x-3)(x+5)} \cdot \frac{-{\color{blue}\rlap{/}}x{\color{red}\rlap{//////}}(x-3)}{3{\color{blue}\rlap{/}}x{\color{green}\rlap{//////}}(x-1)}


    Answer: . -\,\frac{3x+5}{3(x+5)}

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  3. #3
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    Quote Originally Posted by direction View Post
    3x + 12x -5 / 3x - 3x
    ------------ --------
    x + 2x -15 3x - x


    can anyone solve this for me or give some help? im completely stuck.. dotted lines are supposed to be just solid lines, idk how to do it otherwise
    do u mean
    Attached Thumbnails Attached Thumbnails Perform the indicated operations and express in simplest form:-untitled.jpg  
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  4. #4
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    3x + 12x -15 / 3x - 3x
    ------------ --------
    x + 2x -15 3x - x


    sorry, here is the correct version
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  5. #5
    Junior Member
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    Mar 2010
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    Hi direction,

    \frac{3\left(x^2+4x-5\right)}{x^2+2x-15} \cdot \frac{x\left(3-x\right)}{3x\left(x-1\right)} = \frac{{\color{blue}\rlap{/}}3{\color{green}\rlap{///////}}\left(x+5\right){\color{red}\rlap{///////}}\left(x-1\right)}{{\color{green}\rlap{///////}}\left(x+5\right){\color{yellow}\rlap{///////}}\left(x-3\right)}\cdot\frac{{\color{blue}\rlap{/}}x\left({-1}\right){\color{yellow}\rlap{///////}}\left(x-3\right)}{{\color{blue}\rlap{//}}3x{\color{red}\rlap{///////}}\left(x-1\right)}

    Hence, answer is -1
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