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Math Help - Algebra -w. Fractions

  1. #1
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    Question Algebra -w. Fractions

    I've been working on this question for about an hour now, there's probably a really simple solution... I just can't find it.

    here it is,

    b + 3 = b - 1
    _____ _____
    4 2

    please help, if possible.

    thank you, KATrandom

    EDIT: ok so for some reason when I post this the 2 comes to connect to the 4 when it should be under b - 1, sorry 'bout that, they just don't want to be seperated
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  2. #2
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    b + 3 = b - 1
    _____ _____
    4 2

    k first cross multiply
    n then take all d terms to one side n simplify
    n then u can find 'b'
    2b+6=4b-4
    2b-10=0
    b=5
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  3. #3
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    It is slightly simpler just to multiply on both sides by 4. Since 2 divides 4, that clears both fractions.
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  4. #4
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    ya ur correct....could do that either
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  5. #5
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    Quote Originally Posted by KATrandom View Post
    I've been working on this question for about an hour now, there's probably a really simple solution... I just can't find it.

    here it is,

    b + 3 = b - 1
    _____ _____
    4 2

    please help, if possible.

    thank you, KATrandom

    EDIT: ok so for some reason when I post this the 2 comes to connect to the 4 when it should be under b - 1, sorry 'bout that, they just don't want to be seperated
    Another alternative is the get a common denominator:

    \frac{b + 3}{4} = \frac{b - 1}{2}

    \frac{b + 3}{4} = \frac{2(b - 1)}{4}.

    Now since the denominators are equal, so must be the numerators.


    b + 3 = 2(b - 1)

    b + 3 = 2b - 2

    b + 5 = 2b

    b = 5.
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  6. #6
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    thanks :D

    thanks guys, helps a lot, a little confusing but thanks
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