1. ## Another Log related question (this one is bad)

Hello again

well i tried working on my spring break packet again and came across this little gem. which i honestly cannot get my head around.

f(x)=logBASEn[(mn)^x-logBASEm^(n)] , m,n>0

a)find the x and y intercepts.

b)Show the graph of f(x) is equivalent to the line passing through the points you found in part (a).

c)Provide an example sketch from the graphing calculator
I cannot figure out what to input.

d)What happens to the graph when mn=1?

Once again thank you very much and any help is appreciated

-Gus

2. Originally Posted by Danktoker
Hello again

well i tried working on my spring break packet again and came across this little gem. which i honestly cannot get my head around.

f(x)=logBASEn[(mn)^x-logBASEm^(n)] , m,n>0

a)find the x and y intercepts.

b)Show the graph of f(x) is equivalent to the line passing through the points you found in part (a).

c)Provide an example sketch from the graphing calculator
I cannot figure out what to input.

d)What happens to the graph when mn=1?

Once again thank you very much and any help is appreciated

-Gus
syntax for this part of the function is unclear ...

3. That means Log base m to the nth power

Hope that is clear.

THank you

4. How can you have a power on a base without a coefficent? Or do you mean
$Log_mn$
If so then
$f(x)=log_n(mn)^x-log_mn$

A. x & y intercept.

$f(x)=\frac{log_n(mn)^x}{log_mn}$

$f(x)=\frac{xlog_n(n)+xlog(m)}{log_m+log(n)},$

I do not believe you can find the x & y intercept... Just a thought, with just variables and all...

5. indeed this is why i am confused but that is what the problem says.

so what do you suggest i do?

6. I would skip it
But maybe someone else has a better idea.

7. gaaah i cant stand this professor any more...

all my friends got other professors and their nothing like this guy.

he custom makes our problems to be insane.