# Thread: I have a Few Log related questions.

1. ## I have a Few Log related questions.

Well our professor left us quite a bit of homework over Spring Break.
And let just say he hasnt been doing the best job teaching us in class.
(me and alot of the other students agree)

Any way i need help figuring out how to solve the following problems:
20/6-e^2x=4

and

logbase4(4x)-logbase4(x/4)=2

Me and a few classmates have been breaking our heads trying to figure this out. Thank you

-Gus

2. Is the first question $\frac{20}{6-e^{2x}}=4$ ?

If so,

$5=6-e^{2x}$

$e^{2x}=1$

$2x=ln(1)$

$2x=0$

$x=0$

3. Originally Posted by Danktoker
Well our professor left us quite a bit of homework over Spring Break.
And let just say he hasnt been doing the best job teaching us in class.
(me and alot of the other students agree)

Any way i need help figuring out how to solve the following problems:
20/6-e^2x=4

and

logbase4(4x)-logbase4(x/4)=2

Me and a few classmates have been breaking our heads trying to figure this out. Thank you

-Gus

4. For the second one:

$log_4(4x)-log_4(\frac{x}{4})=log_4(16)$

$log_4(4x\div\frac{x}{4})=log_4(16)$

$log_4(\frac{16x}{x})=log_4(16)$

$\therefore x$ can be any real number.

5. Originally Posted by Stroodle
For the second one:

$log_4(4x)-log_4(\frac{x}{4})=log_4(16)$

$log_4(4x\div\frac{x}{4})=log_4(16)$

$log_4(\frac{16x}{x})=log_4(16)$

$\therefore x$ can be any positive real number.
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