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Math Help - I have a Few Log related questions.

  1. #1
    Junior Member
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    I have a Few Log related questions.

    Well our professor left us quite a bit of homework over Spring Break.
    And let just say he hasnt been doing the best job teaching us in class.
    (me and alot of the other students agree)

    Any way i need help figuring out how to solve the following problems:
    20/6-e^2x=4

    and

    logbase4(4x)-logbase4(x/4)=2

    Me and a few classmates have been breaking our heads trying to figure this out. Thank you

    -Gus
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  2. #2
    Senior Member Stroodle's Avatar
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    Is the first question \frac{20}{6-e^{2x}}=4 ?

    If so,

    5=6-e^{2x}

    e^{2x}=1

    2x=ln(1)

    2x=0

    x=0
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  3. #3
    MHF Contributor harish21's Avatar
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    Quote Originally Posted by Danktoker View Post
    Well our professor left us quite a bit of homework over Spring Break.
    And let just say he hasnt been doing the best job teaching us in class.
    (me and alot of the other students agree)

    Any way i need help figuring out how to solve the following problems:
    20/6-e^2x=4

    and

    logbase4(4x)-logbase4(x/4)=2

    Me and a few classmates have been breaking our heads trying to figure this out. Thank you

    -Gus
    sorry.. misread the question!
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  4. #4
    Senior Member Stroodle's Avatar
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    For the second one:

    log_4(4x)-log_4(\frac{x}{4})=log_4(16)

    log_4(4x\div\frac{x}{4})=log_4(16)

    log_4(\frac{16x}{x})=log_4(16)

    \therefore x can be any real number.
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  5. #5
    MHF Contributor
    skeeter's Avatar
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    Quote Originally Posted by Stroodle View Post
    For the second one:

    log_4(4x)-log_4(\frac{x}{4})=log_4(16)

    log_4(4x\div\frac{x}{4})=log_4(16)

    log_4(\frac{16x}{x})=log_4(16)

    \therefore x can be any positive real number.
    ...
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