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Math Help - Can anyone solve this algebra problem?

  1. #1
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    Can anyone solve this algebra problem?

    Need to simplify. I keep getting 1, but apparently that is wrong. Thanks in advance!

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  2. #2
    MHF Contributor harish21's Avatar
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    Quote Originally Posted by Schoolgirlheart View Post
    Need to simplify. I keep getting 1, but apparently that is wrong. Thanks in advance!

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    \frac{9{y^2}-12y+4}{(3y-2)^2} = \frac{9{y^2}-12y+4}{9{y^2}-12y+4} = 1

    OR

    \frac{9{y^2}-12y+4}{(3y-2)^2} = \frac{(3y-2)^2}{(3y-2)^2} = 1

    (a-b)^2 = {a^2}-2ab+{b^2}

    How can this be wrong?! 1 IS the asnwer

    To check your answer, try plugging y=1 in your fraction, and you'll see that the result is satisfied!
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  3. #3
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    Well, if you want to be really hard nosed about it, \frac{y^2- 12y+ 4}{(3y-2)} is equal to 1 for all y except y= 2/3 where it is undefined. The functions f(y)\frac{y^2- 12y+ 4}{(3y-2)} and g(y)= 1 are NOT the same- they have different natural domains.
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  4. #4
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    Thank you for the answers - I now believe 1 is correct. Math teacher wrong....yikes!
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