Hey having trouble with this one guys.
$\displaystyle \dfrac{lim}{x \rightarrow -2} : \dfrac{x}{x+2}$
Cheers
Definitely the wrong forum, but I ain't the po-lice.
$\displaystyle \frac{x}{x+2} = \frac{1}{1+2/x}$
Wait that did nothing..? One sec.
Oh, approach it from the right and left and see what the deal is.
BTW \lim_{x\rightarrow -2} $\displaystyle = \lim_{x\rightarrow -2}$