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Math Help - please help me solve these problems every steps

  1. #1
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    Question please help me solve these problems every steps

    a rectangle is three less than twice as long as it is wide. what are the length and the width if its perimeter is 42 inches?

    a)15, 27 inches
    b) 13,23 inches
    c) 16, 8 inches
    d) 13, 8 inches

    if x is the first of three consecutive integers and the sum of the second and third is 208 then which of the following can be used to solve for x?

    a) x+(x+2)+(x+4=208
    b)2x+3=208
    c)3x+3=208
    d)2x+2=208

    which is factor of: 5x^2 +27x+10

    a) (5x+3)
    b) (x+5)
    c) (3x+5)
    d) ( x+10)
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  2. #2
    MHF Contributor harish21's Avatar
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    Quote Originally Posted by BeBeMala View Post
    a rectangle is three less than twice as long as it is wide. what are the length and the width if its perimeter is 42 inches?

    a)15, 27 inches
    b) 13,23 inches
    c) 16, 8 inches
    d) 13, 8 inches

    if x is the first of three consecutive integers and the sum of the second and third is 208 then which of the following can be used to solve for x?

    a) x+(x+2)+(x+4=208
    b)2x+3=208
    c)3x+3=208
    d)2x+2=208

    which is factor of: 5x^2 +27x+10

    a) (5x+3)
    b) (x+5)
    c) (3x+5)
    d) ( x+10)
    1. let l be the length of the rectangle and let w be the width.
    then, by your question:
     l = 2w-3

    so the perimeler is given by : 2(l+w)= 2((2w-3)+w)
    since perimeter = 42, you have  2(2w-3+w) =42 \rightarrow 6w-6 = 42 so,    w = 8
    then  l = 2w-3=2(8)-3 = 13

    so l=13 and w = 8

    2. if x is the first integer, then x+1 and x+2 are the two consecutive integers after x. the question is saying that (x+1)+(x+2)=208 \rightarrow 2x+3=208

    3. you can factorize  5{x^2} +27x+10 as  5{x^2} +  25x+2x+27 = 5x(x+5)+2(x+5)=(5x+2)(x+5) so one of your factors is ...
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  3. #3
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    Thumbs up

    Quote Originally Posted by harish21 View Post
    1. let l be the length of the rectangle and let w be the width.
    then, by your question:
     l = 2w-3

    so the perimeler is given by : 2(l+w)= 2((2w-3)+w)
    since perimeter = 42, you have  2(2w-3+w) =42 \rightarrow 6w-6 = 42 so,    w = 8
    then  l = 2w-3=2(8)-3 = 13

    so l=13 and w = 8

    2. if x is the first integer, then x+1 and x+2 are the two consecutive integers after x. the question is saying that (x+1)+(x+2)=208 \rightarrow 2x+3=208

    3. you can factorize  5{x^2} +27x+10 as  5{x^2} +  25x+2x+27 = 5x(x+5)+2(x+5)=(5x+2)(x+5) so one of your factors is ...
    Thank you, you made it very easy for me to understand...
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