Please clarify what and denote.
Hi, im in the middle of extending SUVAT equations, im learning from a book so have no tutor to ask about this, i hope someone here can help
if a ball is thrown from 1.2m above ground to a overall height of 2.45m then S=2.45 and So=1.2 correct?
Now when the ball comes back down to be caught in the hand what is S and So?
thanks in advance!
= initial velocity
= the height at a particular time.
Assuming that is correct and assuming that the ball is being caught at exactly the same height in which it was thrown from then =1.2. The initial height will always be 1.2 and will not change since it is a constant and not effected by time.