New to forum, lets see if you can help

Hi, im in the middle of extending SUVAT equations, im learning from a book so have no tutor to ask about this, i hope someone here can help :)

if a ball is thrown from 1.2m above ground to a overall height of 2.45m then S=2.45 and So=1.2 correct?

Now when the ball comes back down to be caught in the hand what is S and So?

thanks in advance!

Please clarify what and denote.

Quote:

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Originally Posted by j55

Hi, im in the middle of extending SUVAT equations, im learning from a book so have no tutor to ask about this, i hope someone here can help :)

if a ball is thrown from 1.2m above ground to a overall height of 2.45m then S=2.45 and So=1.2 correct?

Now when the ball comes back down to be caught in the hand what is S and So?

thanks in advance!

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I will assume that

= initial velocity
while
= the height at a particular time.

Assuming that is correct and assuming that the ball is being caught at exactly the same height in which it was thrown from then =1.2. The initial height will always be 1.2 and will not change since it is a constant and not effected by time.

i thought So was initial position not velocity? in suvat equations U represents initial velocity.
im quite confused because im reading different things in different places.

I learnt u was initial velocity.

The question is rather confusing, I can only assume that the ball is thrown from the hand which is 1.2m above ground so surely they're reversed.

thats what i thought, so if the ball is falling from 1.25m (regardless of how far it is falling) the initial position is 1.25m which is So yes?