Complete the square on:

x^2 - 8x

and

x^2 + 4k

Thanks

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- Mar 27th 2010, 07:14 PMicesta1Complete the square on:
Complete the square on:

x^2 - 8x

and

x^2 + 4k

Thanks - Mar 27th 2010, 07:28 PMProve It
You have to add and subtract the square of half of your coefficient of $\displaystyle x$.

So $\displaystyle x^2 - 8x = x^2 - 8x + (-4)^2 - (-4)^2$

$\displaystyle = \left(x - 4\right)^2 - 16$.

$\displaystyle x^2 + 4k$ is already complete as the coefficient of $\displaystyle x$ is $\displaystyle 0$.