I have solved the simultaneous equations but I think there might have been an easier method. I have x=-2y+3 from the first equation. I don't think its correct. I substituted part of the first equation into the second one.

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- Mar 27th 2010, 06:30 AMStuck ManSimultaneous log equations
I have solved the simultaneous equations but I think there might have been an easier method. I have x=-2y+3 from the first equation. I don't think its correct. I substituted part of the first equation into the second one.

- Mar 27th 2010, 06:36 AMe^(i*pi)
What was the first part of the question? The question is suggesting you use the answer to the previous part of the question to solve this one.

We have

This simplifies to which is a quadratic equation, hence use the formula to solve for given that it must be greater than 0 - Mar 27th 2010, 06:54 AMStuck Man
I wasn't expecting the way you started it. I did something more like the earlier part of the question. I will scan my work in a minute.

- Mar 27th 2010, 06:58 AMStuck Man
The correct scan is attached to this.

- Mar 27th 2010, 07:18 AMStuck Man
I'm not sure if the final line is any use on the left, x=-2y+3.

- Mar 27th 2010, 12:49 PMSoroban
Helolo, Stuck Man!

Quote:

17. Show that: .

Hence, solve: .

Base-change formula:

. .

The system becomes: .

Let: . . .

From [1], we have: .

Substitute into [2]: .

Hence: .

Back-substitute:

Therefore: .

- Mar 28th 2010, 06:52 AMStuck Man
Thanks. I thought there might be different methods of doing the question.