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Math Help - factoring completely

  1. #1
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    factoring completely

    how do you completely factor 2m (to the 3rd power) minus 5m(squared) plus 3m
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  2. #2
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    Quote Originally Posted by blame_canada100 View Post
    how do you completely factor 2m (to the 3rd power) minus 5m(squared) plus 3m
    2m^3 - 5m^2 + 3m

    = m(2m^2 - 5m + 3)

    = m(2m - 3)(m - 1)

    -Dan
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  3. #3
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    answer

    Quote Originally Posted by blame_canada100 View Post
    how do you completely factor 2m (to the 3rd power) minus 5m(squared) plus 3m
    First take out 1 m so you have a degree of two for you equation
    like this
    (^2 means to the second power or squared)

    m(2m^2-5m+3)

    then factor
    I used guess and check
    I tried several combiations until I figured it out
    I tried
    m(2m-1)(m-3)
    and i came out with
    m(2m^2-4m+3)
    almost but the middle number was wrong so
    I tried
    m(2m-3)(m-1)
    I checked and got
    m(2m^2-5m+3)
    bingo!
    thats the answer
    also
    another method of solving is useing the quatdratic formulat

    (-b+or- the sqare root (b^2-4AC))/(2A)
    so you would fill in
    (-(-5) + or - the square root ((-5)^2-(4(2)(3))/((2)(2))

    you will get 3/2 and 1
    so you can fill them in two ways and both will work
    (m-3/2)(m-1)
    or
    (2m-3)(m-1)

    DOnt forget multiplying by the first m you factored out in the begining

    answer

    m(2m-3)(m-1)
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