1. factoring completely

how do you completely factor 2m (to the 3rd power) minus 5m(squared) plus 3m

how do you completely factor 2m (to the 3rd power) minus 5m(squared) plus 3m
2m^3 - 5m^2 + 3m

= m(2m^2 - 5m + 3)

= m(2m - 3)(m - 1)

-Dan

how do you completely factor 2m (to the 3rd power) minus 5m(squared) plus 3m
First take out 1 m so you have a degree of two for you equation
like this
(^2 means to the second power or squared)

m(2m^2-5m+3)

then factor
I used guess and check
I tried several combiations until I figured it out
I tried
m(2m-1)(m-3)
and i came out with
m(2m^2-4m+3)
almost but the middle number was wrong so
I tried
m(2m-3)(m-1)
I checked and got
m(2m^2-5m+3)
bingo!
also
another method of solving is useing the quatdratic formulat

(-b+or- the sqare root (b^2-4AC))/(2A)
so you would fill in
(-(-5) + or - the square root ((-5)^2-(4(2)(3))/((2)(2))

you will get 3/2 and 1
so you can fill them in two ways and both will work
(m-3/2)(m-1)
or
(2m-3)(m-1)

DOnt forget multiplying by the first m you factored out in the begining