how do you completely factor 2m (to the 3rd power) minus 5m(squared) plus 3m

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- April 11th 2007, 03:48 PMblame_canada100factoring completely
how do you completely factor 2m (to the 3rd power) minus 5m(squared) plus 3m

- April 11th 2007, 04:36 PMtopsquark
- April 11th 2007, 09:00 PMhorsejumperanswer
First take out 1 m so you have a degree of two for you equation

like this

(^2 means to the second power or squared)

m(2m^2-5m+3)

then factor

I used guess and check

I tried several combiations until I figured it out

I tried

m(2m-1)(m-3)

and i came out with

m(2m^2-4m+3)

almost but the middle number was wrong so

I tried

m(2m-3)(m-1)

I checked and got

m(2m^2-5m+3)

bingo!

thats the answer

also

another method of solving is useing the quatdratic formulat

(-b+or- the sqare root (b^2-4AC))/(2A)

so you would fill in

(-(-5) + or - the square root ((-5)^2-(4(2)(3))/((2)(2))

you will get 3/2 and 1

so you can fill them in two ways and both will work

(m-3/2)(m-1)

or

(2m-3)(m-1)

DOnt forget multiplying by the first m you factored out in the begining

answer

m(2m-3)(m-1)