Results 1 to 3 of 3

Math Help - trying to make a 3000mL solution...

  1. #1
    Newbie
    Joined
    Sep 2009
    Posts
    7

    trying to make a 3000mL solution...

    Ok, I am definitely victim to the use it or lose it crowd when it comes to math. This is a simple problem but I'm lacking the confidence my logic with it.


    so, I want to make a 3L solution.

    To make a 1L solution, I add 100mL of this 10X reagent with 900mL of water.
    I must then add 700g of a powder to this solution. In the end, the final volume comes out to be 1400mL.

    For the sake of my own curiosity, how do I go about solving this?



    Here's what I've reasoned...

    700g for 1400mL
    to make 3000mL, 3000/1400 = 2.14

    700g x 2.14 = 1498g

    100 x 2.14 = 214mL of 10x soln
    900 x 2.14 = 1926mL of water
    ~~~~ with the outrageous amount of powder, I should get 3L.

    Am I right or wrong? Please help me out with this. thanks
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Newbie
    Joined
    Sep 2009
    Posts
    7
    actually... I think I'm right.

    it would be nice for someone to confirm this though.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    MHF Contributor
    Grandad's Avatar
    Joined
    Dec 2008
    From
    South Coast of England
    Posts
    2,570
    Thanks
    1
    Hello TreeTruffle

    Yes, you're about right, but have rounded too soon, meaning that your answers aren't quite as accurate as they might be.

    Amount of powder = \frac{700 \times 3000}{1400}=1500 gm

    Amount of 10x solution = = \frac{100 \times 3000}{1400}=214 ml (which is what you got)

    Amount of water = \frac{900 \times 3000}{1400}=1929 ml

    Grandad
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 1
    Last Post: September 23rd 2011, 04:39 AM
  2. How to make a proper guess at a particular solution
    Posted in the Differential Equations Forum
    Replies: 5
    Last Post: October 25th 2010, 10:33 PM
  3. General Solution of a differential solution
    Posted in the Differential Equations Forum
    Replies: 4
    Last Post: September 11th 2010, 03:49 AM
  4. Replies: 1
    Last Post: March 24th 2010, 01:14 AM
  5. Replies: 2
    Last Post: September 7th 2009, 03:01 PM

Search Tags


/mathhelpforum @mathhelpforum