1. ## Division Question

How many different solutions are there to this division? different letters stand for different digits and no number begins with zero.

JMO / UK = OK ( what are the numbers)

2. Originally Posted by nazz
How many different solutions are there to this division? different letters stand for different digits and no number begins with zero.

JMO / UK = OK ( what are the numbers)
One solution.
JMO = OK*UK
K cannot be one, because K^2 = 1 = O,. repetition is not allowed.
Let K = 2. Then O = 4
So 42* U2 = JMO.
Product is three digits. U cannot be 3,neither 2. So try one
So 42*12 = 504.
Try other combination, if possible.

3. Hello nazz
Originally Posted by nazz
How many different solutions are there to this division? different letters stand for different digits and no number begins with zero.

JMO / UK = OK ( what are the numbers)
I think the complete set of solutions is:
$\begin{array}{c c c c c}
J&M&O&U&K\\
5&0&4&1&2\\
8&9&6&1&4\\
7&4&1&3&9\\
9&3&1&4&9\\
\end{array}$

Hello nazzI think the complete set of solutions is:
$\begin{array}{c c c c c}
J&M&O&U&K\\
5&0&4&1&2\\
8&9&6&1&4\\
7&4&1&3&9\\
9&3&1&4&9\\
\end{array}$