The sum of two numbers is five times the difference of the numbers. What is the ratio of the largest to the smaller? The answer is 3:2, but I don't know what to do in order to get that. Thanks to anyone who can help.
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Originally Posted by Averee The sum of two numbers is five times the difference of the numbers. What is the ratio of the largest to the smaller? The answer is 3:2, but I don't know what to do in order to get that. Thanks to anyone who can help. Hi, let x be the greater number and y the smaller. Then you know: x + y = 5(x - y) x + y = 5x - 5y 6y = 4x Now divide by y(the samller number) and by 4 Code: 6 x --- = --- 4 y You can simplify the LHS of the equation and you'll get the given result. EB
6 x --- = --- 4 y
Thank you, but how did you get 6y to equal 4x?
Originally Posted by Averee Thank you, but how did you get 6y to equal 4x? we had x + y = 5x - 5y (do you understand how he got to that?) so x + y = 5x - 5y, add 5y to both sides we get x + y + 5y = 5x, now subtract x from both sides, we get y + 5y = 5x - x, now combine the x's and y's 6y = 4x
Ah, thank you. I guess I kept subtracting x and y and getting 4x - 6y = 0. Thanks.
Originally Posted by Averee Ah, thank you. I guess I kept subtracting x and y and getting 4x - 6y = 0. Thanks. but that's the same thing as well 4x - 6y = 0, add 6y to both sides, we get 4x = 6y
I see. I guess I just keep confusing myself, lol. Thanks again.
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