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Thread: Binomial Theorem

  1. March 21st 2010, 11:33 AM #1
    DemonX01
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    Binomial Theorem

    Given that

    (1+x/2)^8(1-x)^6)≡1+Ax+Bx^2...

    find the constants A and B

    how would I solve for them, other than completely expanding each binomial?
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  2. March 21st 2010, 12:37 PM #2
    Plato
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    Quote Originally Posted by DemonX01 View Post
    (1+x/2)^8(1-x)^6)≡1+Ax+Bx^2...

    find the constants A and B
    \left(1+\frac{x}{2}\right)^8=1+4x+14x^2+\cdots
    (1-x)^6=1-x+15x^2+\cdots

    Mulriply those and see what happens.
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