Given that

(1+x/2)^8(1-x)^6)≡1+Ax+Bx^2...

find the constants A and B

how would I solve for them, other than completely expanding each binomial?

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- March 21st 2010, 11:33 AMDemonX01Binomial Theorem
Given that

(1+x/2)^8(1-x)^6)≡1+Ax+Bx^2...

find the constants A and B

how would I solve for them, other than completely expanding each binomial?

- March 21st 2010, 12:37 PMPlato