Given that
(1+x/2)^8(1-x)^6)≡1+Ax+Bx^2...
find the constants A and B
how would I solve for them, other than completely expanding each binomial?
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Given that
(1+x/2)^8(1-x)^6)≡1+Ax+Bx^2...
find the constants A and B
how would I solve for them, other than completely expanding each binomial?