RULE: x times y^(-z) = x / y^z
(2AB/A^2)=(2AB)x(A^-2)
I need to get B in terms of A. I need to get all the 'A' terms grouped together, but i don't know what to do with the powers.
I can get this:
B=-(0.3333A^2)/(2A)
But as you can see i still have more than 1 A. I need to get all the A's together?
Then i get this:
B=(1/6)A
Can anyone confirm if i have done this correct?