How do you do Log base 5 of (x ^2 + x + 4) = 2?
Follow Math Help Forum on Facebook and Google+
Originally Posted by Alan306090 How do you do Log base 5 of (x ^2 + x + 4) = 2? first, change it to an exponential equation ... you'll get a quadratic to solve. don't forget to check your solutions in the original log equation for domain issues.
Originally Posted by skeeter first, change it to an exponential equation ... you'll get a quadratic to solve. don't forget to check your solutions in the original log equation for domain issues. 25 = x ^2 + x + 4 0 = x^2 +x -21 then what? I can't factor it
Originally Posted by Alan306090 25 = x ^2 + x + 4 0 = x^2 +x -21 then what? I can't factor it $\displaystyle x = \frac{-b\pm\sqrt{1^2-4\times 1\times -21}}{2\times 1}=\dots$
View Tag Cloud